A) \[0.5\times {{10}^{23}}\]
B) \[1.5\times {{10}^{23}}\]
C) \[3.5\times {{10}^{23}}\]
D) \[1.8\times {{10}^{32}}\]
Correct Answer: B
Solution :
Molecular weight of \[N{{H}_{3}}\] is 17 According to the mole concept \[17\,gm\] \[N{{H}_{3}}\] has molecules \[=6.02\times {{10}^{23}}\] \[\therefore \,\,1\,gm\] \[N{{H}_{3}}\] has molecules \[=\frac{6.02\times {{10}^{23}}}{17}\] \[\therefore \] \[4.25\,gm\] \[N{{H}_{3}}\] has molecules \[=\frac{6.02\times {{10}^{23}}\times 4.25}{17}=1.5\times {{10}^{23}}\,molecule\]
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