A) 40.3
B) 36.3
C) 24.3
D) 11.3
Correct Answer: C
Solution :
As the given sulphate is isomorphous with \[ZnS{{O}_{4}}.7{{H}_{2}}O\] its formula would be \[MS{{O}_{4}}.7{{H}_{2}}O\].m is the atomic weight of M, molecular weight of \[MS{{O}_{4}}.7{{H}_{2}}O\] \[=m+32+64+126\] \[=m+222\] Hence % of M\[=\frac{m}{m+222}\times 100\]\[=9.87\](given) or \[100m=9.87m+222\times 9.87\]or \[90.13m=222\times 9.87\] or \[m=\frac{222\times 9.87}{90.13}=24.3\].You need to login to perform this action.
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