JEE Main & Advanced Chemistry Some Basic Concepts of Chemistry Question Bank Atomic Molecular and Equivalent masses

  • question_answer The equivalent weight of a metal is 9 and vapour density of its chloride is 59.25. The atomic weight of metal is [Pb. CET 2002]

    A)                 23.9

    B)                 27.3

    C)                 36.3       

    D)                 48.3

    Correct Answer: A

    Solution :

               Given equivalent weight of metal = 9                    Vapour density of metal chloride = 59.25                    \[\therefore \] molecular weight of metal chloride                    \[=2\times V.D=2\times 59.25=118.5\]                    \[\therefore \] valency of metal                    \[=\frac{\text{molecular weight of metal chloride}}{\text{equivalnet weight of metal }+\text{35}\text{.5}}\]                    Valency of metal \[=\frac{118.5}{9+35.5}=\frac{118.5}{44.5}=2.66\]                    Therefore atomic weight of the metal                    =equivalent weight \[\times \] valency                                 \[=9\times 2.66=23.9\]

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