A) \[6.02\times {{10}^{23}}\]
B) \[12.04\times {{10}^{23}}\]
C) \[18.06\times {{10}^{23}}\]
D) \[24.08\times {{10}^{22}}\]
Correct Answer: D
Solution :
\[\because \] 22.4L of a gas at STP has no. of molecules \[=6.023\times {{10}^{23}}\] \[\therefore \] 8.96L of a gas at STP has no. of molecules \[=\frac{6.02\times {{10}^{23}}\times 8.96}{22.4}\]\[=2.408\times {{10}^{23}}\]\[=24.08\times {{10}^{22}}\].
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