JEE Main & Advanced Chemistry Some Basic Concepts of Chemistry Question Bank Atomic Molecular and Equivalent masses

  • question_answer \[4.4\ g\] of an unknown gas occupies \[2.24L\] of volume at standard temperature and pressure. The gas may be [MP PMT 1995]

    A)                 Carbon dioxide    

    B)                 Carbon monoxide

    C)                 Oxygen  

    D)                 Sulphur dioxide

    Correct Answer: A

    Solution :

               \[\because \]   2.24L of gas has mass = 4.4gm                      \[\therefore \]   22.4L of gas has mass \[=\frac{4.4}{2.24}\times 22.4=44\]                                 So given gas is \[C{{O}_{2}}\] because \[C{{O}_{2}}\] has molecular mass=44.

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