A) 2.8 kg
B) 6.4 kg
C) 9.6 kg
D) 96 kg
Correct Answer: B
Solution :
\[{{C}_{2}}{{H}_{4}}+2{{O}_{2}}\to 2C{{O}_{2}}+2{{H}_{2}}O\] \[\because \] 28gm \[{{C}_{2}}{{H}_{4}}\] requires 64gm oxygen \[\therefore \] \[2.8\times {{10}^{3}}\] gm \[{{C}_{2}}{{H}_{4}}\] requires =\[\frac{64}{28}\times 2.8\times {{10}^{3}}gm\] \[=6.4\times {{10}^{3}}gm\] = 6.4kg.
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