A) \[1.4\times {{10}^{-21}}\]g
B) \[1.09\times {{10}^{-21}}\]g
C) \[5.025\times {{10}^{23}}\]g
D) \[16.023\times {{10}^{23}}\]g
Correct Answer: A
Solution :
Molecular weight of \[{{C}_{60}}{{H}_{122}}\]\[=12\times 60+122\times 1\] \[=720+122=842\] \[\because \] \[6\times {{10}^{23}}\]molecule \[{{C}_{60}}{{H}_{122}}\]has mass = 842gm \[\therefore \] 1 molecule \[{{C}_{60}}{{H}_{122}}\]has mass \[\frac{842}{6\times {{10}^{23}}}\] \[=140.333\times {{10}^{-23}}gm\] \[=1.4\times {{10}^{-21}}gm\].
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