JEE Main & Advanced Chemistry Some Basic Concepts of Chemistry Question Bank Atomic Molecular and Equivalent masses

  • question_answer The number of molecule at NTP in 1 ml of an ideal gas will be

    A)                 \[6\times {{10}^{23}}\]    

    B)                 \[2.69\times {{10}^{19}}\]

    C)                 \[2.69\times {{10}^{23}}\]              

    D)                 None of these

    Correct Answer: B

    Solution :

               \[\because \]  22400 ml at NTP has \[6.023\times {{10}^{23}}\]molecule                    \[\therefore \] 1 ml at NTP has =\[\frac{6.023\times {{10}^{23}}}{22400}\]                                                  =\[0.0002688\times {{10}^{23}}\]\[=2.69\times {{10}^{19}}\].


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