A) 34
B) 32
C) 17
D) 8
Correct Answer: C
Solution :
Let weight of metal oxide = 100gm Weight of oxygen = 32gm \[\therefore \] weight of metal \[=100-32=68gm\] Equivalent weight of oxide \[=\frac{\text{wt}\text{. of metal}}{\text{wt}\text{. of oxygen}}\times 8\] \[=\frac{68}{32}\times 8=17\].You need to login to perform this action.
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