JEE Main & Advanced Chemistry Some Basic Concepts of Chemistry Question Bank Atomic Molecular and Equivalent masses

  • question_answer The vapour density of a gas is 11.2. The volume occupied by 11.2 g of the gas at ATP will be [Bihar CET 1995]

    A)                 11.2 L    

    B)                 22.4 L

    C)                 1 L         

    D)                 44.8 L

    Correct Answer: A

    Solution :

               Molecular weight \[=2\times V.D\]\[=2\times 11.2=22.4\]                    \[\because \]  22.4gm  of gas occupies 22.4L at S.T.P.                                 \[\therefore \]  11.2gm of gas occupies \[\frac{22.4}{22.4}\times 11.2=11.2L\].


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