JEE Main & Advanced Chemistry Some Basic Concepts of Chemistry Question Bank Atomic Molecular and Equivalent masses

  • question_answer One litre of a gas at STP weight 1.16 g it can possible be [AMU 1992]

    A)                 \[{{C}_{2}}{{H}_{2}}\]    

    B)                 \[CO\]

    C)                 \[{{O}_{2}}\]       

    D)                 \[C{{H}_{4}}\]

    Correct Answer: A

    Solution :

               \[\because \]  1L of gas at S.T.P. weight 1.16g                    \[\therefore \]  22.4 L of gas at S.T.P. weight \[=22.4\times 1.16\]        \[=25.984\approx 26\] This molecular weight indicates that given compound is \[{{C}_{2}}{{H}_{2}}\].


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