A) \[{{C}_{2}}{{H}_{2}}\]
B) \[CO\]
C) \[{{O}_{2}}\]
D) \[C{{H}_{4}}\]
Correct Answer: A
Solution :
\[\because \] 1L of gas at S.T.P. weight 1.16g \[\therefore \] 22.4 L of gas at S.T.P. weight \[=22.4\times 1.16\] \[=25.984\approx 26\] This molecular weight indicates that given compound is \[{{C}_{2}}{{H}_{2}}\].
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