JEE Main & Advanced Chemistry Some Basic Concepts of Chemistry Question Bank Atomic Molecular and Equivalent masses

  • question_answer 74.5 g of a metallic chloride contain 35.5 g of chlorine. The equivalent weight of the metal is                   [CPMT 1986]

    A)                 19.5       

    B)                 35.5

    C)                 39.0       

    D)                 78.0

    Correct Answer: C

    Solution :

               wt. of metallic chloride\[=74.5\]                    wt. of chlorine = 35.5                    \[\therefore \] wt. of metal \[=74.5-35.5=39\]                    Equivalent weight of metal \[=\frac{\text{weight of metal}}{\text{weight of chlorine}}\times 35.5\]                                               \[=\frac{39}{35.5}\times 35.5=39\]


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