JEE Main & Advanced Chemistry Structure of Atom / परमाणु संरचना Question Bank Atomic models and Planck's quantum theory

  • question_answer
    The ionisation potential of a hydrogen atom is ?13.6 eV. What will be the energy of the atom corresponding to \[n=2\] [Pb. CET 2000]

    A)                 ?3.4 eV                

    B)                 ?6.8 eV

    C)                 ?1.7 eV

    D)                 ? 2.7 eV

    Correct Answer: A

    Solution :

               Energy of an electron \[E=\frac{-{{E}_{0}}}{{{n}^{2}}}\]                    For energy level \[(n=2)\]                                 \[E=-\frac{13.6}{{{(2)}^{2}}}=\frac{-13.6}{4}=-3.4eV\].


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