A) \[ns\ np\ nd(n-1)f\]
B) \[ns\ np(n-1)d\ (n-2)f\]
C) \[ns\ np(n-1)d\ (n-1)f\]
D) \[ns(n-1)d\ n(n-1)f\]
Correct Answer: B
Solution :
Higher the (n+1) value higher is the energy associated with orbitals.
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