| ASSERTION: Sharper is the curvature of spot on a charged body, lesser will be the surface charge density at that point. |
| REASON: Electric field is non zero inside a charged conductor. |
A) If both assertion and reason are true and reason is the correct explanation of assertion.
B) If both assertion and reason are true and reason is not the correct explanation of assertion.
C) If assertion is true but reason is false.
D) If both assertion and reason are false.
E) If assertion is false but reason is true.
Correct Answer: D
Solution :
Surface of a charged conductor is always an equipotential surface, whatever may be its shape. Hence \[\sigma R=\]constant, at every point on the surface of charged conductor i.e. at the sharpest point \[\left( R\to 0 \right)\]of the surface, charge density will be maximum. A uniformly charged conductor exerts no electrostatic force on a point charge located anywhere inside the conductor or electric field is zero.
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