question_answer

Aromatisation of n-heptane by passing over \[(A{{l}_{2}}{{O}_{3}}+C{{r}_{2}}{{O}_{3}})\] catalyst at 773 K gives [DCE 2004]

A) Benzene

B) Toluene

C) Mixture of both

D) Heptylene

Correct Answer: B

Solution :

           \[\underset{n\text{-heptane}}{\mathop{\underset{C{{H}_{2}}}{\overset{\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,{{H}_{2}}}}\,}{\mathop{\underset{{{H}_{2}}C}{\overset{{{H}_{2}}C}{\mathop{\,\,\,\,\,|}}}\,\ \ \ \ \ \ \ \ \underset{C{{H}_{2}}}{\overset{C{{H}_{3}}}{\mathop{|\,\,\,\,\,\,}}}\,}}}\,\,\,\,\,\,\,}}\,\underset{773K}{\mathop{\xrightarrow{A{{l}_{2}}{{O}_{3}}/C{{r}_{2}}{{O}_{3}}}}}\,\]