JEE Main & Advanced Chemistry Hydrocarbons Question Bank Aromatic Hydrocarbon

  • question_answer Anhydrous \[AlC{{l}_{3}}\] is used in the Friedel-Craft?s reaction because it is [CBSE PMT 1991]

    A) Electron rich

    B) Soluble in ether

    C) Insoluble to chloride and aluminium ions

    D) Electron deficient

    Correct Answer: D

    Solution :

               AlCl3 is an electron deficient compound. It generates electrophile in the reaction \[C{{H}_{3}}Cl+AlC{{l}_{3}}\to \underset{\text{Electrophile}}{\mathop{C{{H}_{3}}^{+}}}\,+AlC{{l}_{4}}^{-}\]

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