A) Kolbe?s reaction
B) Williamson?s synthesis
C) Wurtz reaction
D) Sandmeyer reaction
Correct Answer: A
Solution :
Kolbe?s methods - Electrolysis of a concentrated aqueous solution of either sodium or potassium salts of saturated mono carboxylic acids yields higher alkanes at anode. \[C{{H}_{3}}COONa\]⇌ \[C{{H}_{3}}CO{{O}^{-}}+Na+\] Anode : \[2C{{H}_{3}}CO{{O}^{-}}\xrightarrow{-2{{e}^{-}}}C{{H}_{3}}-C{{H}_{3}}+2C{{O}_{2}}\] Cathode : \[2N{{a}^{+}}+2{{e}^{-}}\to 2Na\] \[2Na+2{{H}_{2}}O\to 2NaOH+{{H}_{2}}\]
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