A) \[NO_{2}^{-}\]
B) \[NO_{2}^{+}\]
C) \[NO_{3}^{-}\]
D) \[N{{O}_{2}}\]
Correct Answer: B
Solution :
\[HO-N{{O}_{2}}+{{H}^{+}}HS{{O}_{4}}^{-}\to \]\[{{H}_{2}}O+\underset{\begin{smallmatrix} \,\,\,\text{Nitronium}\,\text{ion} \\ \text{(attacking species)} \end{smallmatrix}}{\mathop{N{{O}_{2}}^{+}+HS{{O}_{4}}^{-}}}\,\]
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