A) \[A-(i);\,B-(ii);\,C-(iv);\,D-(iii)\]
B) \[A-(ii);\,B-(i);\,C-(iii);\,D-(iv)\]
C) \[A-(i);\,B-(ii);\,C-(iii);\,D-(iv)\]
D) \[A-(ii);\,B-(i);\,C-(iv);\,D-(iii)\]
Correct Answer: D
Solution :
\[\frac{1}{4}+\frac{1}{4\times 5}\,+\frac{1}{4\times 5\times 6}\,=\frac{1}{4}\,\left( 1-\frac{1}{5}+\frac{1}{30} \right)\] \[=\frac{1}{4}\times \frac{37}{30}\,=\frac{37}{12}\times \frac{1}{10}\,=0.3083\] \[0.3333\times 0.25\times 0.499\,\times \,0.125\times 24\] \[=0.3\times 0.25\,\times 0.5\times 0.125\times 24\] \[=\frac{3}{10}\,\times \frac{25}{100}\times \frac{5}{10}\times \,\frac{125}{1000}\times 24\] \[=\frac{1}{8}\] (approx.) \[0.48=\frac{48}{100}=\frac{12}{25}\] Required sum = 12 + 25 = 37 2.002 + 7.9 {2.8 ? 6.3 (3.6 ? 1.5) + 15. 6 = 2.02 + 7.9 {2.8 ? 6. 3 \[\times \] 2.1 + 15.6} =2. 002 + 7.9 {5. 17}=42.845
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