• # question_answer  DIRECTIONS: Match Column-I with Column-II and select the correct answer using the codes given below the columns. A)  $A-(iv);\,B-(iii);\,C-(ii);\,D-(i)$ B)  $A-(iii);\,B-(iv);\,C-(ii);\,D-(i)$ C)  $A-(iii);\,B-(iv);\,C-(i);\,D-(ii)$ D)  $A-(iv);\,B-(iii);\,C-(i);\,D-(ii)$

$x\times \frac{5}{4}\,-x\times \frac{5}{14}=25\Rightarrow \,\frac{25x}{28}=25\Rightarrow x=28$ where ?x? is required number A?s hare $=\frac{3}{16}x,\,B's$ $=\frac{x}{4}$ and C?s share $=x-\left( \frac{3}{16}x+\frac{x}{4} \right)=\frac{9}{16}x$ where x= total amount. Now, $\frac{9x}{16}=81\Rightarrow \,x=144$ $\therefore$ B?s share $=144\times \frac{1}{4}\,=36$ Money spent $=\frac{5}{6}$ Remaining money $=1-\frac{5}{6}\,=\frac{1}{6}$ Money earned $=\frac{1}{12}$ Total money with him $=\frac{1}{6}\,+\frac{1}{12}\,=\frac{1}{4}$  $\frac{1}{8}\text{th}$ part of pencil = black. $\Rightarrow$            Remaining part of pencil $=1-\frac{7}{8}\,=\frac{7}{8}$ Yellow part $=\frac{1}{2}\times \frac{7}{8}\,=\frac{7}{16}$ Blue part $=1-\left( \frac{1}{8}-\frac{7}{16} \right)=\frac{7}{16}$ But given blue part = 3.5 cm $\therefore$Total length $=3.5\times \frac{16}{7}\,=8\,cm$