A) 2 : 7
B) 16 : 35
C) 4 : 13
D) 7 : 8
Correct Answer: B
Solution :
\[\frac{A}{B}=\frac{2}{3},\,\frac{B}{C}=\frac{4}{5},\,\frac{C}{D}=\frac{6}{7}\] From 2nd and 3rd expression we have \[A=\frac{2}{3}\,B,\,B=\frac{4}{5},\,C=\frac{6}{7}D\] \[B=\frac{4}{5}\times \frac{6}{7}D\] \[A=\frac{2}{3}\times \,\frac{4}{5}\times \frac{6}{7}D\] \[\frac{A}{D}=\frac{2}{\bcancel{3}}\times \frac{4}{5}\,\times \frac{{{\bcancel{6}}^{2}}}{7}=\frac{16}{35}\]
You need to login to perform this action.
You will be redirected in
3 sec
