6th Class Mathematics Arithmetic Question Bank Arithmetic

  • question_answer If \[63.3605\,=6A=\frac{3}{13}\,+3C+\frac{3}{D}\,+5E,\] then the value of 4A + 7B + 6C + D + 3E is

    A) 47.6003                      

    B) 4.7603

    C) 147.6003       

    D) 47.603

    Correct Answer: C

    Solution :

     \[63.3605\,=6\times 10+3\times 1\,+3\times \frac{1}{10}\,+6\times \frac{1}{100}\] \[+0\times \frac{1}{1000}+5\times \frac{1}{10000}\] On comparing with the given expression we get \[A=10,\,B=1,\,C=\frac{1}{10},\,D=100,\,E=\frac{1}{10,000}\] \[\therefore \] Required expression = 40 + 7 + 0.6 + 100 + 0.0003 = 147. 6003   


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