2. Questions Bank
  3. 10th Class
  4. Mathematics
  5. Arithmetic Progressions

10th Class Mathematics Arithmetic Progressions Question Bank Arithmetic Progressions

  • question_answer
    The sum to 'n' natural numbers is \[{{S}_{1}}\] sum of the squares of 'n' natural numbers is \[{{S}_{2}}\] and sum of the cubes of 'n' natural numbers is \[{{S}_{3}}\] Which of the following is equal to \[9S_{2}^{2}\]?

    A)  \[(1-8{{S}_{1}}){{S}_{2}}\]          

    B)         \[{{S}_{3}}(1+8{{S}_{1}})\]

    C)  \[{{S}_{1}}(1+8{{S}_{2}})\]                         

    D)  \[{{S}_{1}}(1-8{{S}_{3}})\]

    Correct Answer: B

    Solution :

                    \[L.C.M.\] \[\frac{6}{14}and\frac{2}{7}\] \[\Rightarrow \] \[\frac{L.C.M.(6,2)}{H.C.F.(14,7)}=\frac{6}{7}\] \[\text{7}\times \text{13}+\text{13}=\text{1}0\text{4}=\text{23}\times \text{13}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner