A) \[P+Q\]
B) \[2P+3Q\]
C) \[2Q\]
D) \[Q\]
Correct Answer: D
Solution :
Obviously\[{{S}_{n}}=\frac{n}{2}\{2P+(n-1)Q\}\], hence\[d=Q\]. Aliter: \[d={{T}_{2}}-{{T}_{1}}\]\[=({{S}_{2}}-{{S}_{1}})-{{S}_{1}}\] \[={{S}_{2}}-2{{S}_{1}}=2P+Q-2P=Q.\]
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