A) 1190
B) 1197
C) 1210
D) None of these
Correct Answer: C
Solution :
The given numbers are 13, 17, ..... 97. This is an AP with first term 13 and common difference 4. Let the number of terms be\[n\]. Then \[97=13+(n-1)4\] \[\Rightarrow \]\[4n=88\]\[\Rightarrow \]\[n=22\] Therefore the sum of the numbers \[=\frac{22}{2}[13+97]=11(110)=1210\].
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