A) 55350
B) 57228
C) 97015
D) 62140
Correct Answer: A
Solution :
Series \[108+117+........+999\] is an A.P. where \[a=108\], common difference \[d=9\], \[n=\frac{999}{9}-\frac{99}{9}=111-11=100\] Hence required sum =\[\frac{100}{2}(108+999)=50\times 1107=55350\].
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