A) 1680
B) 1683
C) 1681
D) 1682
Correct Answer: B
Solution :
We get series 3, 6, 9, 12,........ 99. Here\[n=\frac{99}{3}=33,\ a=3,\ d=3\], therefore \[S=\frac{33}{2}\left\{ 2\times 3+(33-1)3 \right\}\] \[=\frac{33}{2}\times 102=33\times 51=1683\].
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