A) 3200
B) 1600
C) 200
D) 2800
Correct Answer: A
Solution :
First term \[a=2\] and common difference \[d=4\]and\[n=40\]. Then \[{{S}_{n}}=\frac{n}{2}[2a+(n-1)d]\] \[=20[4+39\times 4]=20[4+156]\]\[=160\times 20=3200\].
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