JEE Main & Advanced Mathematics Sequence & Series Question Bank Arithmetic Progression

  • question_answer
    If \[{{a}_{1}}={{a}_{2}}=2,\ {{a}_{n}}={{a}_{n-1}}-1\ (n>2)\], then \[{{a}_{5}}\]is

    A) 1

    B) \[-1\]

    C) 0

    D) \[-2\]

    Correct Answer: B

    Solution :

    Obviously, \[{{a}_{3}}={{a}_{2}}-1=2-1=1\] \[{{a}_{4}}={{a}_{3}}-1=1-1=0\] \[{{a}_{5}}={{a}_{4}}-1=0-1=-1.\]


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