A) 3
B) 7
C) 5
D) - 2
Correct Answer: C
Solution :
\[2x,\ x+8,\ 3x+1\] are in A.P. Therefore \[(x+8)=\frac{(2x)+(3x+1)}{2}=\frac{5x+1}{2}\] \[\Rightarrow \] \[2x+16=5x+1\] \[\Rightarrow \] \[3x=15\] \[\Rightarrow \] \[x=5\].
You need to login to perform this action.
You will be redirected in
3 sec
