A) \[p+q+r\]
B) \[p+q-r\]
C) \[p+r-q\]
D) \[p-q-r\]
Correct Answer: B
Solution :
Given that, \[{{T}_{p}}=a+(p-1)d=q\] ?..(i) and \[{{T}_{q}}=a+(q-1)d=p\] ?.. (ii) From (i) and (ii), we get \[d=-\frac{(p-q)}{(p-q)}=-1\] Putting value of \[d\] in equation (i), then \[a=p+q-1\] Now, \[{{r}^{th}}\] term is given by A.P. \[{{T}_{r}}=a+(r-1)d=(p+q-1)+(r-1)(-1)\] \[=p+q-r\] Note: Students should remember this question as a formula.
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