A) \[3\pi \,c{{m}^{2}}\]
B) \[6\pi \,c{{m}^{2}}\]
C) \[9\pi \,c{{m}^{2}}\]
D) \[7\pi \,c{{m}^{2}}\]
Correct Answer: A
Solution :
In quadrilateral ABCD \[\angle A+\angle B+\angle C+\angle D={{360}^{o}}\] \[\angle A+{{90}^{o}}+{{90}^{o}}+{{60}^{o}}={{360}^{o}}\Rightarrow \angle A={{120}^{o}}\] Now, area of shaded region \[=\frac{{{120}^{o}}}{{{360}^{o}}}\times \pi \times {{3}^{2}}\] \[=\frac{1}{3}\times \pi \times 3\times 3=3\pi \,c{{m}^{2}}\]
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