A) 2
B) \[\frac{1}{4}\]
C) \[\frac{1}{2}\]
D) \[\frac{2}{3}\]
Correct Answer: B
Solution :
It is given that E is the mid point of BC. \[\therefore \] \[BE=EC=\frac{1}{2}BC\] Now, \[ar(\Delta DEC)=k\,ar(ABCD)\] \[\Rightarrow \]\[\frac{1}{2}\times EC\times h=k\times BC\times h\] {where h is the height} \[\Rightarrow \]\[\frac{1}{2}\times \frac{1}{2}BC\times h=k\times BC\times h\Rightarrow k=\frac{1}{4}\]You need to login to perform this action.
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