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9th Class Mathematics Areas of Parallelograms and Triangles Question Bank Area of Parallelogram & Triangle

  • question_answer
    The difference of the areas of two squares drawn on two line segments of different lengths is 51 sq. cm. Find the length of the greater line segment if one is longer than the other by 3 cm.

    A)  7 cm                           

    B)  9 cm

    C)  11 cm                         

    D)  16 cm

    Correct Answer: B

    Solution :

    (b): Let the length of the smaller line segment = x cm. The length of larger line segment \[=\left( x+3 \right)\] cm. According to the question, \[{{(x+3)}^{2}}-{{x}^{2}}=51\] \[\Rightarrow \]\[{{x}^{2}}+6x-9-{{x}^{2}}=51\] \[\Rightarrow \]\[6x=51-9=42\] \[\Rightarrow \] \[x=\frac{42}{6}=7\] The required length \[=x+2=7+2=9\]cm.        


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