A) \[\sqrt{3}\] sq. unit/sec
B) 10 sq. unit/sec
C) \[10\sqrt{3}\] sq. unit/sec
D) \[\frac{10}{\sqrt{3}}\] sq. unit/sec
Correct Answer: C
Solution :
If x is the length of each side of an equilateral triangle and A is its area, then \[A=\frac{\sqrt{3}}{4}{{x}^{2}}\Rightarrow \frac{dA}{dt}=\frac{\sqrt{3}}{4}2x\frac{dx}{dt}\] Here, \[x=10\,\,cm\] and \[\frac{dx}{dt}=2\,\,cm/sec\] Þ \[A=10\sqrt{3}\] Sq. unit per sec.
You need to login to perform this action.
You will be redirected in
3 sec
