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JEE Main & Advanced Mathematics Applications of Derivatives Question Bank Application in Mechanics and Rate Measurer

  • question_answer
    The radius of a sphere is measured to be 20 cm with a possible error of 0.02 of a cm. The consequent error in the surface of the sphere is

    A)            \[10.5\] sq cm

    B)            5.025 sq cm

    C)            10.05 sq cm

    D)            None of these

    Correct Answer: C

    Solution :

               \[S=4\pi {{r}^{2}}\] \[\therefore \delta S=8\pi r\delta x=8\pi \times 20\times .02=10.05\,\,sq.cm.\]


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