A) \[16\,c{{m}^{2}}/\sec \]
B) \[8\,c{{m}^{2}}/\sec \]
C) \[32\,c{{m}^{2}}/\sec \]
D) None of these
Correct Answer: A
Solution :
Given that rate of metal increasing \[=4cm/\sec =v=\frac{da}{dt}\] We know that area of square sheet =a2, (where a is side). \[\therefore \frac{dA}{dt}=2a\frac{da}{dt}=2\times 2\times 4=16c{{m}^{2}}/\sec \].
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