JEE Main & Advanced Mathematics Applications of Derivatives Question Bank Application in Mechanics and Rate Measurer

  • question_answer
     A body moves according to the formula \[v=1+{{t}^{2}}\], where v is the velocity at time t. The acceleration after 3 sec will be   (v in cm/sec) [MP PET 1988]

    A)            \[24\,cm/{{\sec }^{2}}\]

    B)            \[12\,cm/{{\sec }^{2}}\]

    C)            \[6\,cm/{{\sec }^{2}}\]

    D)            None of these

    Correct Answer: C

    Solution :

               Acceleration \[f=\frac{dv}{dt}=2t,\] then acceleration after 3 second \[\therefore \frac{dA}{dt}=2\pi R\frac{dR}{dt}=1.2\pi c{{m}^{2}}\].


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