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JEE Main & Advanced Mathematics Applications of Derivatives Question Bank Application in Mechanics and Rate Measurer

  • question_answer
    The equation of motion of a stone thrown vertically upward from the surface of a planet is given by \[s=10\,\,t-3{{t}^{2}}\], and the units of s and t are cm and sec respectively. The stone will return to the surface of the planet after

    A)            \[\frac{10}{3}\sec \]

    B)            \[\frac{5}{3}\sec \]

    C)            \[\frac{20}{3}\sec \]

    D)            \[\frac{5}{6}\sec \]

    Correct Answer: A

    Solution :

               \[\frac{ds}{dt}=10-6t=v\]                    But \[v=0\] (at maximum height), \[\therefore t=\frac{10}{6}\]                    Therefore, the stone will return in \[2\times \frac{10}{6}=\frac{10}{3}\sec .\]


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