JEE Main & Advanced Mathematics Applications of Derivatives Question Bank Application in Mechanics and Rate Measurer

  • question_answer
    The equation of motion of a stone, thrown vertically upwards is \[s=ut-6.3{{t}^{2}},\]where the units of s and t are cm and sec. If the stone reaches at maximum height in 3 sec, then u =

    A)            \[18.9\,\,cm/\sec \]

    B)            \[12.6\,\,cm/\sec \]

    C)            \[37.8\,\,cm/\sec \]

    D)            None of these

    Correct Answer: C

    Solution :

               Velocity of particle at the maximum height \[\frac{ds}{dt}=0\] \[\Rightarrow u-12.6t=0\Rightarrow u=12.6t=37.8\,cm/s.\]


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