A) \[2\theta \]
B) \[\theta /3\]
C) \[\theta \]
D) \[\theta /2\]
Correct Answer: C
Solution :
\[\because \]\[\tan \varphi =\frac{2\sqrt{{{h}^{2}}-ab}}{a+b}\] Þ \[\tan \varphi =\frac{2\sqrt{{{\cos }^{2}}\theta -({{\cos }^{2}}\theta -{{\sin }^{2}}\theta )}}{\cos \theta -\sin \theta +\cos \theta +\sin \theta }\]=\[\frac{2\sin \theta }{2\cos \theta }\] Þ \[\tan \varphi =\tan \theta \] Þ \[\varphi =\theta \].
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