A) \[{{\tan }^{-1}}\left( \frac{1}{3} \right)\]
B) \[{{\tan }^{-1}}3\]
C) \[{{\tan }^{-1}}\frac{\sqrt{33}}{5}\]
D) \[{{\tan }^{-1}}\frac{5}{\sqrt{33}}\]
Correct Answer: C
Solution :
\[\alpha ={{\tan }^{-1}}\frac{2\sqrt{\frac{49}{4}-4}}{5}={{\tan }^{-1}}\frac{\sqrt{33}}{5}\].
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