A) \[{{\theta }_{1}}={{\theta }_{2}}\]
B) \[{{\theta }_{1}}=2{{\theta }_{2}}\]
C) \[2{{\theta }_{1}}={{\theta }_{2}}\]
D) None of these
Correct Answer: A
Solution :
Obviously \[{{\theta }_{1}}={{\tan }^{-1}}\left( \frac{2\sqrt{\frac{49}{4}-12}}{3+4} \right)={{\tan }^{-1}}\left( \frac{1}{7} \right)\] and\[{{\theta }_{2}}={{\tan }^{-1}}\left( \frac{2\sqrt{\frac{25}{4}-6}}{6+1} \right)={{\tan }^{-1}}\left( \frac{1}{7} \right)\]. Hence, \[{{\theta }_{1}}={{\theta }_{2}}\].
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