A) \[HCOOK\xrightarrow{\text{electrolysis}}\]
B) \[CH{{I}_{3}}+6Ag+CH{{I}_{3}}\xrightarrow{\Delta }\]
C) \[C{{H}_{3}}C{{H}_{2}}OH\underset{443{}^\circ C}{\mathop{\xrightarrow{\text{Conc}\text{. }{{H}_{2}}S{{O}_{4}}}}}\,\]
D) \[B{{e}_{2}}C+{{H}_{2}}O\to \]
Correct Answer: B
Solution :
Acetylene can be obtained by the reaction of silver and chloroform (or iodo form) \[2CH{{I}_{3}}+6Ag\xrightarrow{\Delta }\underset{\text{acetylene}}{\mathop{{{C}_{2}}{{H}_{2}}+6AgI}}\,\]
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