A) \[C{{H}_{2}}=C{{H}_{2}}\]
B) \[{{C}_{6}}{{H}_{6}}\]
C) \[C{{H}_{3}}-C\equiv CH\]
D) \[C{{H}_{3}}-C\equiv C-C{{H}_{ 3}}\]
Correct Answer: D
Solution :
\[C{{H}_{3}}-C\equiv C-C{{H}_{3}}\] has not acidic character.
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