A) \[C{{H}_{4}}\]
B) \[{{C}_{2}}{{H}_{6}}\]
C) \[{{C}_{2}}{{H}_{4}}\]
D) \[{{C}_{2}}{{H}_{2}}\]
Correct Answer: D
Solution :
\[2CH\equiv CH+2Na\to 2CH\equiv {{C}^{-}}N{{a}^{+}}+{{H}_{2}}\]
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