A) Na
B) \[HCl\text{ and }{{H}_{2}}O\]
C) \[KOH\text{ in }{{C}_{2}}{{H}_{5}}OH\]
D) Zn
Correct Answer: C
Solution :
\[R-C{{H}_{2}}-CC{{l}_{2}}-R\xrightarrow{KOH\,+\,{{C}_{2}}{{H}_{5}}OH}\]\[R-C\equiv C-R+2\,HCl\] This reaction is an example of dehydrohalogenation Hence, alcoholic \[KOH\]is used as a reagent.
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