A) Zero
B) One
C) Two
D) Three
Correct Answer: B
Solution :
\[CH\equiv CH+{{H}_{2}}O\underset{HgS{{O}_{4}}}{\mathop{\xrightarrow{\text{dil}\text{.}\,{{H}_{2}}S{{O}_{4}}\,}}}\,C{{H}_{2}}=C-OH\to \]\[C{{H}_{3}}-\underset{\underset{O}{\mathop{||}}\,}{\mathop{C}}\,-H\]
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